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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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∑m=1nm2\sum\limits_{{m=1}}^n m^2 is equal to
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Correct option: C
n(n+1)(2n+1)6\frac{n(n+1)(2 n+1)}{6}
Option C (n(n+1)(2n+1)6\frac{n(n+1)(2 n+1)}{6}) is correct because it is the standard formula for the sum of the squares of the first n natural numbers.

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