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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

What would be the pressure inside a small air bubble of

1.0\,mm

radius situated just below the surface of water?

\left[ {T = 72 \times {{10}^{ - 3}}\,N/m;{\rho _0} = 1.013 \times {{10}^5}\frac{N}{{{m^2}}}} \right]

View answer and explanation

Correct option: D

1.027 \times {10^5}\frac{N}{{{m^2}}}

Option D (

1.027 \times {10^5}\frac{N}{{{m^2}}}

) is correct because it is calculated by adding the excess pressure inside the air bubble to the atmospheric pressure.

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