How much $\mathrm{Ca}\left(\mathrm{NO}_3\right)_2,$ in $\mathrm{mg},$ must be present in $50 \mathrm{~ml}$ of a solution with $2.35 \mathrm{~ppm}$ of $\mathrm{Ca}?$

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Application +4 | -1

How much

\mathrm{Ca}\left(\mathrm{NO}_3\right)_2,

\mathrm{mg},

must be present in

50 \mathrm{~ml}

of a solution with

2.35 \mathrm{~ppm}

\mathrm{Ca}?

View answer and explanation

Correct option: D

0.48

Option D (0.48) is correct because it represents the calculated mass of

\mathrm{Ca(NO_3)_2}

in mg, present in the given solution based on the ppm of Ca.

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