JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

Sum of the first

20 \mathrm{terms}

of the AP

2,3 \frac{1}{4}, 4 \frac{1}{2}, 5 \frac{3}{4}, \ldots

View answer and explanation

Correct option: B

277 \frac{1}{2}

Option B (

277 \frac{1}{2}

) is correct because it is the sum of the first 20 terms of the given arithmetic progression, calculated using the formula for the sum of an AP.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}