JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

The value of

{\left( {0.16} \right)^{{{\log }_{2.5}}\left( {\frac{1}{3} + \frac{1}{{{3^2}}} + \frac{1}{{{3^3}}} + \; \ldots \mathrm{to}\;\infty } \right)}}

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Correct option: D

Option D (4) is correct because after simplifying the logarithmic expression and applying the properties of exponents, the result is 4.

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