Skip to main content
Back to LIMITS

JEE MATHEMATICS MCQ: LIMITS

1 Medium
1 of 1
Analyzing +4 | -1
If lim⁡x→0sin⁡(αx−ln⁡(1+βx))e3x−3x−1=1\lim \limits_{{x \rightarrow 0}} \frac{\sin (\alpha x-\ln (1+\beta x))}{e^{3 x}-3 x-1}=1, then α+2β\alpha+2 \beta is equal to
View answer and explanation
Correct option: C
9
Option C (9) is correct because by using L'Hopital's rule and series expansion, we find that α=β\alpha = \beta and β2=9\beta^2 = 9, leading to α+2β=9\alpha + 2\beta = 9.

More Questions from LIMITS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.