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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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There is some change in length when 33000 N tensile force is applied on a steel rod of area of cross section 10−3m2{10^{ - 3}}{m^2} . The change in temperature required to produce the same elongation of elasticity is 3×1011 N/m23 \times {10^{11}}\,N/{m^2} and the co-efficient of linear expansion of steel is 1.1×10−5/ ∘C1.1 \times {10^{ - 5}}/{\,^ \circ }C
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Correct option: C
10∘C{10^ \circ }C
Option C (10∘C{10^ \circ }C) is correct because it is the temperature change calculated using the relationship between tensile force, Young's modulus, area, and coefficient of linear expansion.

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