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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

There are

n

different books and

p

copies of each. The number of ways in which a selection can be made from them is

View answer and explanation

Correct option: C

{\left( {p + 1} \right)^n} - 1

Option C (

{\left( {p + 1} \right)^n} - 1

) is correct because each book can be selected in p+1 ways (0 to p copies), and we subtract 1 for the case where no book is selected.

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