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JEE MATHEMATICS MCQ: PERMUTATIONS

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The number of 6-digit numbers that can be made with the digits

1,2,3

and

4

and having exactly two pairs of digits is

View answer and explanation

Correct option: C

1080

Option C (1080) is correct because the number of ways to select two digits to appear twice is

{}^4C_2

, and the number of arrangements is

\frac{6!}{2! \times 2!}

.

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