JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

x=\sum_{n=0}^{\infty} a^n, y=\sum_{n=0}^{\infty} b^n, z=\sum_{n=0}^{\infty} c^n

where

a, b, c

are in

A . P

. and

|a|<1,|b|<1,|c|<1, a b c \neq 0

, then

View answer and explanation

Correct option: C

\frac{1}{x}, \frac{1}{y}, \frac{1}{z}

are in A.P.

Option C (

\frac{1}{x}, \frac{1}{y}, \frac{1}{z}

are in A.P.) is correct because it follows from the given conditions that a, b, c are in A.P., and a, b, c can be expressed in terms of x, y, z.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}