JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7}+\frac{1}{9}-\frac{1}{11}+\cdots=\frac{\pi}{4}

, then value of

\frac{1}{1 \cdot 3}+\frac{1}{5 \cdot 7}+\frac{1}{9 \cdot 11}+\cdots

View answer and explanation

Correct option: A

\frac{\pi}{8}

Option A (

\frac{\pi}{8}

) is correct because it is derived by recognizing the given series as a manipulation of the Leibniz formula for pi.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

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(B \cup C)-A

a,b,c

a,x,b

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{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

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G P

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\frac{3}{4}