JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Hard

1 of 1

Understanding +4 | -1

The number of all possible

5-

tuples

\left(a_{1}, a_{2}, a_{3}\right.

a_{4}, a_{5}

) such that

a_{1}+a_{2} \sin x+a_{3} \cos x+a_{4} \sin 2 x+a_{5}

\cos 2 x=0

holds for all

x

View answer and explanation

Correct option: B

Option B (1) is correct because the given equation holding for all

x

implies that all coefficients must be zero, leading to only one possible 5-tuple (0, 0, 0, 0, 0).

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