If $ 2^{x}=4^{y}=8^{z} $ and $ ^{x y z}=288 $, then $ \frac{1}{2 x}+\frac{1}{4 y}+\frac{1}{8 z}= $

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

2^{x}=4^{y}=8^{z}

and

^{x y z}=288

, then

\frac{1}{2 x}+\frac{1}{4 y}+\frac{1}{8 z}=

View answer and explanation

Correct option: D

11 / 96

Option D (11/96) is correct because solving for x, y, and z and then substituting into the expression yields 11/96.

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