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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If 210+29⋅31+28⋅32+…+2×39+310=S−2112^{10}+2^{9} \cdot 3^{1}+2^{8} \cdot 3^{2}+\ldots+2 \times 3^{9}+3^{10}=S-2^{11} then S\mathrm{S} is equal to:
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Correct option: B
3113^{11}
Option B (3113^{11}) is correct because the given series is a G.P., and by applying the G.P. sum formula and rearranging, we find S = 3113^{11}.

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