JEE PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

The vectors

\vec{A}=\hat{i}+2 \hat{j}+3 \hat{k}

and

\vec{B}=2 \hat{i}-\hat{j}

are ___ to each other.

View answer and explanation

Correct option: A

\vec{A} \perp \vec{B}

Option A (

\vec{A} \perp \vec{B}

) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

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\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}