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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

The displacement

x

of a body in motion is given by

x=a \sin (\omega t+\theta)

. The time at which the displacement is maximum is

View answer and explanation

Correct option: B

\left(\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right)

Option B (

\left(\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right)

) is correct because it represents the time when the sine function reaches its maximum value of 1.

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