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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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The needle of a dip circle shows an apparent dip of

45^{\circ}

in a particular position and

53^{\circ}

when the circle is rotated through

90^{\circ}

. Find the true dip.

View answer and explanation

Correct option: C

39^{\circ}

Option C (

39^{\circ}

) is correct because the true dip is calculated using the formula involving the apparent dips in two perpendicular positions.

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Curie temperature is the one above which A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is

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X

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\mu_{\mathrm{d}}, \mu_{\mathrm{p}}

\mu_{\mathrm{f}}

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