JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

0 \leq \mathrm{x} \leq \pi

, then the solution of the equation

16^{\sin ^2 x}+16^{\cos ^2 x}-10

is given by

x

equal to-

View answer and explanation

Correct option: A

\pi / 6, \pi / 3

Option A (

\pi / 6, \pi / 3

) is correct because these are the solutions to the trigonometric equation derived from the given exponential equation within the specified range.

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