JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

Let

a_1, a_2, a_3, \ldots

be terms are in

\mathrm{AP}

, if

\frac{a_1+a_2+\ldots+a_p}{a_1+a_2+\ldots+a_q}=\frac{p^2}{q^2}, p \neq q

, then

\frac{a_6}{a_{21}}

equals

View answer and explanation

Correct option: D

\frac{11}{41}

Option D (

\frac{11}{41}

) is correct because by using the formula for the sum of an AP and substituting p=11 and q=41, we can find the ratio of a6/a21.

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