The wavelength of red light from He-Ne laser is ${\rm{633}}\,\,{\rm{nm}}$ in air but ${\rm{474}}\,\,{\rm{nm}}$ in the aqueous humor inside the eye ball. Then the speed of red light through the aqueous humor is

$2.25\,\, \times \,\,{10^8}\,\,{\rm{m}}{{\rm{s}}^{ - 1}}$

$3\,\, \times \,\,{10^8}\,\,{\rm{m}}{{\rm{s}}^{ - 1}}$

$1.34\,\, \times \,\,{10^8}\,\,{\rm{m}}{{\rm{s}}^{ - 1}}$

$2.5\,\, \times \,\,{10^8}\,\,{\rm{m}}{{\rm{s}}^{ - 1}}$

JEE PHYSICS MCQ: RAY OPTICS

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Application +4 | -1

The wavelength of red light from He-Ne laser is

\mathrm{633}\,\,\mathrm{nm}

in air but

\mathrm{474}\,\,\mathrm{nm}

in the aqueous humor inside the eye ball. Then the speed of red light through the aqueous humor is

View answer and explanation

Correct option: C

2.25\,\, \times \,\,{10^8}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}

Option C (

2.25\, \times \, {10^8}\,\mathrm{m}{\mathrm{s}^{ - 1}}

) is correct because it is the speed of light in the aqueous humor calculated using the ratio of wavelengths.