Two identical heaters of ${\rm{220}}\,\,{\rm{V , 1000 W}}$ are placed in parallel with each other across ${\rm{220}}\,\,{\rm{V}}$ line, then the combined power is

$\begin{array}{*{20}{l}} {{\rm{2000}}\,\,{\rm{W}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{1000}}\,\,{\rm{W}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{500}}\,\,{\rm{W}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{4000}}\,\,{\rm{W}}} \end{array}$

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

Two identical heaters of

\mathrm{220}\,\,\mathrm{V , 1000 W}

are placed in parallel with each other across

\mathrm{220}\,\,\mathrm{V}

line, then the combined power is

View answer and explanation

Correct option: B

\begin{array}{llllllllllllllllllll} {\mathrm{2000}\,\,\mathrm{W}} \end{array}

Option B (2000 W) is correct because the total power in a parallel circuit is the sum of individual powers.