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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1
If a particle is moving with velocity v(t)=cos⁡  πtv\left( t \right) = \cos \,\,\pi t along a straight line such that at t=0,   s=4t = 0,\;\,s = 4 its position function is given by
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Correct option: C
1π  sin⁡  πt  +  4\frac{1}{\pi }\,\,\sin \,\,\pi t\,\, + \,\,4
Option C (1π sin⁡ πt + 4\frac{1}{\pi }\,\sin \,\pi t\, + \,4) is correct because it represents the position function obtained by integrating the velocity function and applying the initial condition.

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