JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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The dimensions of Wien’s constant are

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Correct option: B

\left[ {{M^0}L{T^0}K} \right]

Option B ([

{M^0}L{T^0}K

]) is correct because Wien's constant has dimensions of length times temperature.

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\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

\mathrm{ms}^{-1} \text {. }

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\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}