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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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The rate of flow of liquid in a tube of radius rr, length ll, whose ends are maintained at a pressure difference pp is V=πNpr4ηlV=\frac{\pi N p r^4}{\eta l}, where η\eta is coefficient of the viscosity and NN is
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Correct option: B
18\frac{1}{8}
Option B (18\frac{1}{8}) is correct because the correct formula for the rate of flow of liquid is V=πpr48ηlV=\frac{\pi p r^4}{8 \eta l}.

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