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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If ω\omega is a complex cube root of unity, then the value of ω99+ω100+ω101{\omega ^{99}} + {\omega ^{100}} + {\omega ^{101}} is
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Correct option: D
0
Option D (0) is correct because the sum of consecutive powers of omega (ω\omega) where the powers differ by 1, and are multiples of 3, is always 0.

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