JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

The solution of the equation

{\left[ {\sin \,\,x + \cos \,\,x} \right]^{1 + \sin 2x}} = 2

- \,\pi \le x \le \pi

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Correct option: C

\frac{\pi }{4}

Option C (π/4) is correct because substituting x = π/4 into the equation satisfies the given condition.

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