JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Hard

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Analyzing +4 | -1

The function

f\left( x \right) = x\sqrt {ax - {x^2}} ,a > 0

View answer and explanation

Correct option: A

Increases on the interval

\left( {0,\;3a/4} \right)

Option A (Increases on the interval

\left( {0,\;3a/4} \right)

) is correct because the derivative of the function is positive in that interval, indicating an increasing function.

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

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a

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\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)