JEE PHYSICS MCQ: WAVES

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Application +4 | -1

Two aeroplanes

A

and

B

are approaching cach other and their velocities are

108 \mathrm{~km} \mathrm{~h}^{-1}

and

144 \mathrm{~km} \mathrm{~h}^{-1}

respectively. The frequency of a note emitted by

A

as heard by the passengers in

B

1170 \mathrm{~Hz}

. Calculate the frequency of the note heard by the passenger in A. Velocity of sound

=350 \mathrm{~ms}^{-1}

View answer and explanation

Correct option: A

960 \mathrm{~Hz}

Option A (

960 \mathrm{~Hz}

) is correct because it is calculated using the Doppler effect formula, considering both the source and observer are moving towards each other.

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3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V