NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

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The energy density associated with electric field

\vec{E}

and magnetic field

\vec{B}

of an electromagnetic wave in free space is given by

\left(\varepsilon_{0}-\right.

permittivity of free space,

\mu_{0}

- permeability of free space)

View answer and explanation

Correct option: B

U_{E}=\frac{\varepsilon_{0} E^{2}}{2}, \, U_{B}=\frac{B^{2}}{2 \mu_{0}}

Option B (

U_{E}=\frac{\varepsilon_{0} E^{2}}{2}, \, U_{B}=\frac{B^{2}}{2 \mu_{0}}

) is correct because it represents the energy density associated with electric and magnetic fields in an electromagnetic wave.

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{E_X}

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{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right]

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E = 50\sin \,(500x - 10 \times {10^{10}}t)\,v/m.

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\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}}