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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of the series 12!+14!+16!+…\frac{1}{{2!}} + \frac{1}{{4!}} + \frac{1}{{6!}} + \ldots is equal to
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Correct option: B
(e−1)22e\frac{{{{\left( {e - 1} \right)}^2}}}{{2e}}
Option B ((e−1)22e\frac{{{{\left( {e - 1} \right)}^2}}}{{2e}}) is correct because the series can be expressed in terms of e and simplified to this expression.

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