If $\mathop \smallint \limits_{\log 2}^x \,\,\frac{1}{{\sqrt {{e^x} - \,\,1} }}\,\,dx = \frac{\pi }{6}$ is equal to

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\int \limits_{\log 2}^x \,\,\frac{1}{{\sqrt {{e^x} - \,\,1} }}\,\,dx = \frac{\pi }{6}

is equal to

View answer and explanation

Correct option: C

\log \,\,4

Option C (

\log \,4

) is correct because after solving the definite integral with the given limits and substitution, we find that x =

\log \,4

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