The average of the squares of the numbers $0,\;1,\;2,\;3,4,\;...,\;n,$ is

$\frac{1}{2}n\left( {n + 1} \right)$

$\frac{1}{6}\left( {n + 1} \right)\left( {2n + 1} \right)$

$\frac{1}{6}n\left( {n + 1} \right)$

JEE MATHEMATICS MCQ: STATISTICS

1 Easy

1 of 1

Application +4 | -1

The average of the squares of the numbers

0,\;1,\;2,\;3,4,\;...,\;n,

View answer and explanation

Correct option: B

\frac{1}{6}n\left( {2n + 1} \right)

Option B (

\frac{1}{6}n(2n + 1)

) is correct because it is the average of the squares of the numbers from 0 to n.

Practice All Chapter MCQs →

{x_1},{x_2}, \ldots ,{x_n}

\bar X,

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-2,