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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1
If u=a2cos⁡2θ+b2sin⁡2θ+a2sin⁡2θ+b2cos⁡2θu=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta} then the difference between the maximum and minimum values of u2u^{2} is given by
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Correct option: A
(a−b)2(a-b)^{2}
Option A ((a-b)²) is correct because after simplifying the expression for u² and finding its maximum and minimum values, the difference between them is (a-b)².

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