JEE MATHEMATICS MCQ: SET THEORY

1 Easy

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Analyzing +4 | -1

Let

S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\}

and

T=\left\{x \in \mathbb{Z}: x^2-7|x|+9 \leq 0\right\}

. Then the number of elements in

S \cap T

View answer and explanation

Correct option: D

Option D is correct because by solving the inequalities for S and T, we find that the intersection S ∩ T contains 3 elements.

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