What is the volume of hydrogen liberated at ${\rm{NTP}}$ by the amount of charge which liberates ${\rm{0}}{\rm{.3175}}\,{\rm{ g}}$ of copper?

$\begin{array}{*{20}{l}} {{\rm{112 }}\,{\rm{cc}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{224 }}\,{\rm{cc}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{56 }}\,{\rm{cc}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{1120 }}\,{\rm{cc}}} \end{array}$

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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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What is the volume of hydrogen liberated at

\mathrm{NTP}

by the amount of charge which liberates

\mathrm{0}\mathrm{.3175}\,\mathrm{ g}

of copper?

View answer and explanation

Correct option: B

\begin{array}{llllllllllllllllllll} {\mathrm{112 }\,\mathrm{cc}} \end{array}

Option B (112 cc) is correct because it is the volume of hydrogen liberated at NTP, calculated using Faraday's laws of electrolysis and the equivalent weights of hydrogen and copper.

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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