JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

(a, 0) ; a>0

is the point where the curve

y=\sin 2 x-\sqrt{3} \sin x

cuts the

X

-axis first,

A

is the area bounded by this part of the curve, the origin and the positive

X

-axis, then

View answer and explanation

Correct option: A

4 A+8 \cos a=7

Option A (

4 A+8 \cos a=7

) is correct because after finding the value of 'a' and the area A, substituting them into the equation yields a true statement.

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