Skip to main content
Back to ELLIPSE

JEE MATHEMATICS MCQ: ELLIPSE

1 Medium
1 of 1
Analyzing +4 | -1
The locus of the mid-points of the chords of the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 whose poles are on the auxiliary circle on the tangents at the extremities of which intersect on the auxiliary circle, is
View answer and explanation
Correct option: D
x2+y2=a2(x2a2+y2b2)2x^2+y^2=a^2\left(\frac{x^2}{a^2}+\frac{y^2}{b^2}\right)^2
Option D (x2+y2=a2(x2a2+y2b2)2x^2+y^2=a^2\left(\frac{x^2}{a^2}+\frac{y^2}{b^2}\right)^2) is correct because it represents the locus of mid-points of chords whose poles lie on the auxiliary circle.

More Questions from ELLIPSE

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.