JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy

1 of 1

Analyzing +4 | -1

Statement (S): Humphrey series discovered in

\mathrm{H}

atomic spectra has lowest energy radiations.

Explanation (E): The series belongs to

n_1=6.

View answer and explanation

Correct option: C

Both S and E are correct and E is correct explanation of S

Option C is correct because the Humphrey series corresponds to transitions to n1=6, and transitions to higher energy levels result in lower energy radiations.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

Which of the following is paramagnetic? The time taken by the electron in one complete revolution in the

n^{\text {th }}

Bohr's orbit of the hydrogen atom is The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency '

\mathrm{A}

\times 10^{12}

hertz and that has a radiant intensity in that direction of

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

watt per steradian. 'A' and 'B' are respectively Quantum number which defines the orientation of orbital present in a subshell is Maximum number of electrons associated with

\ell = 1,\,\,m = 0

in magnesium atom is The nucleus and an atom can be assumed to be spherical. The radius of the nucleus of mass no. A is given by

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.

. The atomic radius of atom is 1 Å. If the mass no. is 64, the fraction of the atomic volume that is occupied by nucleus is: