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NEET UG CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1
Which of the following can be used for the preparation of propane
(a) CH3CH=CH2→ΔH2/NiC{H_3}CH = C{H_2}\xrightarrow[\Delta ]{{{H_2}/Ni}} (b) CH3CH2CH2Cl→(ii)H3O+(i)Mg/etherC{H_3}C{H_2}C{H_2}Cl\xrightarrow[{(ii){H_3}O + }]{{(i)Mg/ether}}
(c) CH3CH2CH2I→1500CHI+Red′ P′C{H_3}C{H_2}C{H_2}I\xrightarrow[{{{150}^0}C}]{{HI + {\mathop\mathrm{Re}\nolimits} d'\,P'}} (d) CH3CH2CH2COONa→SodalimeC{H_3}C{H_2}C{H_2}COONa\xrightarrow{{\mathrm{Sodalime}}}
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Correct option: D
a, b, c and d
Option B (Pd/BaSO4Pd/BaS{O_4} or CaCO3CaC{O_3} in quinoline or xylene) is correct because Lindlar's catalyst is palladium supported on barium sulfate or calcium carbonate, poisoned with quinoline or xylene.

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