The value of $\mathop {\lim }\limits_{x \to 2} \frac{{{e^{3x - 6}} - 1}}{{\sin \left( {2 - x} \right)}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

The value of

\lim\limits_{x \to 2} \frac{{{e^{3x - 6}} - 1}}{{\sin \left( {2 - x} \right)}}

View answer and explanation

Correct option: C

- 3

Option C (-3) is correct because by applying L'Hopital's rule, the limit can be evaluated to -3.

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