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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If f  (x)=∫x2x2+1  e−t2 dtf\,\,\left( x \right) = \int \nolimits_{{x^2}}^{{x^2} + 1} \,\,{e^{ - {t^2}}}\,dt, then f  (x)f\,\,\left( x \right) increases in
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Correct option: D
(− ∞,   0)\left( { - \,\infty ,\;\,0} \right)
Option D ((− ∞,   0- \,\infty ,\;\,0)) is correct because the derivative of the function is positive when x < 0, indicating that the function is increasing in that interval.

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