JEE CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)

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\mathrm{C}(\text {diamond})\rightarrow \mathrm{C}(\text {graphite})+\mathrm{X} \mathrm{~kJ} \mathrm{~mol}^{-1}

\begin{aligned} & \mathrm{C}(\text {diamond})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+\mathrm{Y} \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{C}(\text {graphite})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+\mathrm{Z~kJ} \mathrm{~mol}^{-1} \end{aligned}

At constant temperature. Then

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Correct option: D

X = Y – Z

Option D (X = Y – Z) is correct because it is derived from Hess's Law by manipulating the given thermochemical equations.

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