JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Understanding +4 | -1

Function

\sin ^{-1} \sqrt{x}

is defined in the interval

View answer and explanation

Correct option: B

[0,1]

Option B ([0,1]) is correct because the domain of

\sin^{-1} \sqrt{x}

requires

0 \le x \le 1

to ensure a real and defined value.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f^{-1}(x)

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}