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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
If v=At+Bt2+Ct3v = \frac{A}{t} + B{t^2} + C{t^3} , where vv is velocity, t is time and A,B and C are constants, then the dimensional formula of B is
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Correct option: D
[M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]
Option D ([M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]) is correct because each term in the equation must have the same dimensions as velocity (LT⁻¹). Therefore, Bt2Bt^2 must have dimensions of LT⁻¹, implying B has dimensions of LT−3LT^{-3}.

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