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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
The equation of a wave on a string of linear mass density 0.04  kgm−10.04\,\,kg{m^{ - 1}} is given by y=0.02(m)  sin⁡[2π(t0.04(s)−x0.50(m))]y = 0.02\left( m \right)\,\,\sin \left[ {2\pi \left( {\frac{t}{{0.04\left( s \right)}} - \frac{x}{{0.50\left( m \right)}}} \right)} \right]. The tension in the string is
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Correct option: A
6.25  N6.25\,\,N
Option A (6.25 N6.25\,N) is correct because it is the tension in the string calculated using the wave equation and linear mass density.

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