The value of $\mathop \smallint \nolimits_{{e^{ - 1}}}^{{e^2}} \,\,\left| {\,\frac{{{{\log }_e}\,\,x}}{x}\,} \right|\,\,dx$ is

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Application +4 | -1

The value of

\int \nolimits_{{e^{ - 1}}}^{{e^2}} \,\,\left| {\,\frac{{{{\log }_e}\,\,x}}{x}\,} \right|\,\,dx

View answer and explanation

Correct option: B

\frac{5}{2}

Option B (

\frac{5}{2}

) is correct because the integral is split into two parts based on the absolute value, and then solved using substitution.

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