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JEE MATHEMATICS MCQ: PERMUTATIONS

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How many numbers lying between 999 and 10000 can be formed with the help of the digits 0, 2, 3, 6, 7, 8 when the digits are not be repeated?

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Correct option: C

300

Option C (300) is correct because it calculates the number of 4-digit numbers formed with the given digits, excluding those starting with 0.

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