If $4\,\,\cos \,\,{\rm{\theta }} - 3\,\,\sec \,\,{\rm{\theta }} = 2\tan \,\,{\rm{\theta }},{\rm{\;then}}\,\,{\rm{\theta }}$ is equal to

$n\pi + {\left( { - 1} \right)^n}\,\,\frac{\pi }{6}$

$n\pi + {\left( { - 1} \right)^n}\,\,\frac{{3\pi }}{{10}}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

4\,\,\cos \,\,\mathrm{\theta } - 3\,\,\sec \,\,\mathrm{\theta } = 2\tan \,\,\mathrm{\theta },\mathrm{\;then}\,\,\mathrm{\theta }

is equal to

View answer and explanation

Correct option: A

n\pi + {\left( { - 1} \right)^n}\,\,\frac{\pi }{{10}}

Option A (

n\pi + {\left( { - 1} \right)^n}\frac{\pi }{{10}}

) is correct because it represents the general solution of the given trigonometric equation after simplification and solving for

\theta

Practice All Chapter MCQs →

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