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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE
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Consider the following statements
I. The canonical forms have no real existence.
II. The molecule does not exist for a certain fraction of time in one canonical form and for other fractions of time in other canonical forms.
III. There is no such equilibrium between the canonical forms as we have between tautomeric forms (keto and enol) in tautomerism.
IV. The molecule such as has a single structure which is the resonance hybrid of the canonical forms and which cannot such as be depicted by a single Lewis structure.
Which of the above statements are correct?
I. The canonical forms have no real existence.
II. The molecule does not exist for a certain fraction of time in one canonical form and for other fractions of time in other canonical forms.
III. There is no such equilibrium between the canonical forms as we have between tautomeric forms (keto and enol) in tautomerism.
IV. The molecule such as has a single structure which is the resonance hybrid of the canonical forms and which cannot such as be depicted by a single Lewis structure.
Which of the above statements are correct?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the statements accurately describe the nature of canonical forms and resonance hybrids.
More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE
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The hybridization in sulphur dioxide is
has the same geometry as:
The pair of molecules forming strongest hydrogen bonds are
Paramagnetism is shown by
Which statement is correct?
Assertion (A) : is a weaker Lewis acid than .
Reason (R) : The planar molecule is stabilised to a greater extent than by -bonding.
Reason (R) : The planar molecule is stabilised to a greater extent than by -bonding.