NEET UG CHEMISTRY MCQ: HYDROCARBONS

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The compound

\mathrm{X}

in the following reaction is

\mathrm{CH}_3 \mathrm{C} \equiv \mathrm{CCH}_3 \frac{\text { (i) } \mathrm{H}_2 / \mathrm{Pt}}{\text { (ii) } \mathrm{Br}_2} \mathrm{X}

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Correct option: C

dl-2,3-Dibromobutane

Option D (Meso-2,3 Dibromobutane) is correct because the syn addition of hydrogen followed by anti addition of bromine to but-2-yne leads to the formation of the meso compound.

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